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6x^2=960
We move all terms to the left:
6x^2-(960)=0
a = 6; b = 0; c = -960;
Δ = b2-4ac
Δ = 02-4·6·(-960)
Δ = 23040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23040}=\sqrt{2304*10}=\sqrt{2304}*\sqrt{10}=48\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{10}}{2*6}=\frac{0-48\sqrt{10}}{12} =-\frac{48\sqrt{10}}{12} =-4\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{10}}{2*6}=\frac{0+48\sqrt{10}}{12} =\frac{48\sqrt{10}}{12} =4\sqrt{10} $
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