308=2(10x)+2(2x)+2(20)+150-50

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Solution for 308=2(10x)+2(2x)+2(20)+150-50 equation: 



308=2(10x)+2(2x)+2(20)+150-50

We move all terms to the left:

308-(2(10x)+2(2x)+2(20)+150-50)=0

We add all the numbers together, and all the variables

-(232x+320)+308=0

We get rid of parentheses

-232x-320+308=0

We add all the numbers together, and all the variables

-232x-12=0

We move all terms containing x to the left, all other terms to the right

-232x=12

x=12/-232

x=-3/58

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