(6x+1)=(3x-10)+(x+19)

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Solution for (6x+1)=(3x-10)+(x+19) equation: 



(6x+1)=(3x-10)+(x+19)

We move all terms to the left:

(6x+1)-((3x-10)+(x+19))=0

We get rid of parentheses

6x-((3x-10)+(x+19))+1=0



We calculate terms in parentheses: -((3x-10)+(x+19)), so:

(3x-10)+(x+19)

We get rid of parentheses

3x+x-10+19

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We get rid of parentheses

6x-4x-9+1=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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