5(y-3)+14=2(y+10)

Solution for 5(y-3)+14=2(y+10) equation:

5(y-3)+14=2(y+10)

We move all terms to the left:

5(y-3)+14-(2(y+10))=0

We multiply parentheses

5y-(2(y+10))-15+14=0


We calculate terms in parentheses: -(2(y+10)), so:

2(y+10)

We multiply parentheses

2y+20

Back to the equation:

-(2y+20)


We add all the numbers together, and all the variables

5y-(2y+20)-1=0

We get rid of parentheses

5y-2y-20-1=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7