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3(x-1)-7=2(x+1)+9
We move all terms to the left:
3(x-1)-7-(2(x+1)+9)=0
We multiply parentheses
3x-(2(x+1)+9)-3-7=0
We calculate terms in parentheses: -(2(x+1)+9), so:We add all the numbers together, and all the variables
2(x+1)+9
We multiply parentheses
2x+2+9
We add all the numbers together, and all the variables
2x+11
Back to the equation:
-(2x+11)
3x-(2x+11)-10=0
We get rid of parentheses
3x-2x-11-10=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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