(3x-11)=(8x-9)+(3x+12)

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Solution for (3x-11)=(8x-9)+(3x+12) equation: 



(3x-11)=(8x-9)+(3x+12)

We move all terms to the left:

(3x-11)-((8x-9)+(3x+12))=0

We get rid of parentheses

3x-((8x-9)+(3x+12))-11=0



We calculate terms in parentheses: -((8x-9)+(3x+12)), so:

(8x-9)+(3x+12)

We get rid of parentheses

8x+3x-9+12

We add all the numbers together, and all the variables

11x+3

Back to the equation:

-(11x+3)



We get rid of parentheses

3x-11x-3-11=0

We add all the numbers together, and all the variables

-8x-14=0

We move all terms containing x to the left, all other terms to the right

-8x=14

x=14/-8

x=-1+3/4

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