(6x*6x)-15=(5x*5x)-2x

Solution for (6x*6x)-15=(5x*5x)-2x equation:

(6x*6x)-15=(5x*5x)-2x

We move all terms to the left:

(6x*6x)-15-((5x*5x)-2x)=0

We add all the numbers together, and all the variables

(+6x*6x)-((+5x*5x)-2x)-15=0

We get rid of parentheses

6x*6x-((+5x*5x)-2x)-15=0


We calculate terms in parentheses: -((+5x*5x)-2x), so:

(+5x*5x)-2x

We add all the numbers together, and all the variables

-2x+(+5x*5x)

We get rid of parentheses

-2x+5x*5x

Wy multiply elements

25x^2-2x

Back to the equation:

-(25x^2-2x)


Wy multiply elements

36x^2-(25x^2-2x)-15=0

We get rid of parentheses

36x^2-25x^2+2x-15=0

We add all the numbers together, and all the variables

11x^2+2x-15=0

a = 11; b = 2; c = -15;
Δ = b2-4ac
Δ = 22-4·11·(-15)
Δ = 664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{664}=\sqrt{4*166}=\sqrt{4}*\sqrt{166}=2\sqrt{166}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{166}}{2*11}=\frac{-2-2\sqrt{166}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{166}}{2*11}=\frac{-2+2\sqrt{166}}{22}
$