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(6/(x-1))-(4/(3x+3))=0
Domain of the equation: (x-1))!=0
x∈R
Domain of the equation: (3x+3))!=0We calculate fractions
x∈R
(18x+18)/((x-1))*3x+(-4x+4)/((x-1))*3x=0
We multiply all the terms by the denominator
(18x+18)+(-4x+4)=0
We get rid of parentheses
18x-4x+18+4=0
We add all the numbers together, and all the variables
14x+22=0
We move all terms containing x to the left, all other terms to the right
14x=-22
x=-22/14
x=-1+4/7
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