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(6/x+1)-1/2=(4/3x+3)
We move all terms to the left:
(6/x+1)-1/2-((4/3x+3))=0
Domain of the equation: x+1)!=0
x∈R
Domain of the equation: 3x+3))!=0We get rid of parentheses
x∈R
6/x-((4/3x+3))+1-1/2=0
We calculate fractions
(-((4*x*2)/3x^2+(-9x^2)/3x^2+18x/3x^2+1=0
We can not solve this equation
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