(2x-6)+(60-x)=32

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Solution for (2x-6)+(60-x)=32 equation: 



(2x-6)+(60-x)=32

We move all terms to the left:

(2x-6)+(60-x)-(32)=0

We add all the numbers together, and all the variables

(2x-6)+(-1x+60)-32=0

We get rid of parentheses

2x-1x-6+60-32=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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