(6-7x)(8+5x)=0

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Solution for (6-7x)(8+5x)=0 equation:



(6-7x)(8+5x)=0
We add all the numbers together, and all the variables
(-7x+6)(5x+8)=0
We multiply parentheses ..
(-35x^2-56x+30x+48)=0
We get rid of parentheses
-35x^2-56x+30x+48=0
We add all the numbers together, and all the variables
-35x^2-26x+48=0
a = -35; b = -26; c = +48;
Δ = b2-4ac
Δ = -262-4·(-35)·48
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-86}{2*-35}=\frac{-60}{-70} =6/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+86}{2*-35}=\frac{112}{-70} =-1+3/5 $

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