(4x-4)(x+4)=0

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Solution for (4x-4)(x+4)=0 equation:



(4x-4)(x+4)=0
We multiply parentheses ..
(+4x^2+16x-4x-16)=0
We get rid of parentheses
4x^2+16x-4x-16=0
We add all the numbers together, and all the variables
4x^2+12x-16=0
a = 4; b = 12; c = -16;
Δ = b2-4ac
Δ = 122-4·4·(-16)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-20}{2*4}=\frac{-32}{8} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+20}{2*4}=\frac{8}{8} =1 $

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