(6x-1)(3x-2)=(6x+1)(3x+2)

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Solution for (6x-1)(3x-2)=(6x+1)(3x+2) equation: 



(6x-1)(3x-2)=(6x+1)(3x+2)

We move all terms to the left:

(6x-1)(3x-2)-((6x+1)(3x+2))=0

We multiply parentheses ..

(+18x^2-12x-3x+2)-((6x+1)(3x+2))=0



We calculate terms in parentheses: -((6x+1)(3x+2)), so:

(6x+1)(3x+2)

We multiply parentheses ..

(+18x^2+12x+3x+2)

We get rid of parentheses

18x^2+12x+3x+2

We add all the numbers together, and all the variables

18x^2+15x+2

Back to the equation:

-(18x^2+15x+2)



We get rid of parentheses

18x^2-18x^2-12x-3x-15x+2-2=0

We add all the numbers together, and all the variables

-30x=0

x=0/-30

x=0

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