(5y-7)-(2y-35)=3-(1-4y)

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Solution for (5y-7)-(2y-35)=3-(1-4y) equation: 



(5y-7)-(2y-35)=3-(1-4y)

We move all terms to the left:

(5y-7)-(2y-35)-(3-(1-4y))=0

We add all the numbers together, and all the variables

(5y-7)-(2y-35)-(3-(-4y+1))=0

We get rid of parentheses

5y-2y-(3-(-4y+1))-7+35=0



We calculate terms in parentheses: -(3-(-4y+1)), so:

3-(-4y+1)

determiningTheFunctionDomain
-(-4y+1)+3

We get rid of parentheses

4y-1+3

We add all the numbers together, and all the variables

4y+2

Back to the equation:

-(4y+2)



We add all the numbers together, and all the variables

3y-(4y+2)+28=0

We get rid of parentheses

3y-4y-2+28=0

We add all the numbers together, and all the variables

-1y+26=0

We move all terms containing y to the left, all other terms to the right

-y=-26

y=-26/-1

y=+26

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