35=-5(2y-1)

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Solution for 35=-5(2y-1) equation: 



35=-5(2y-1)

We move all terms to the left:

35-(-5(2y-1))=0



We calculate terms in parentheses: -(-5(2y-1)), so:

-5(2y-1)

We multiply parentheses

-10y+5

Back to the equation:

-(-10y+5)



We get rid of parentheses

10y-5+35=0

We add all the numbers together, and all the variables

10y+30=0

We move all terms containing y to the left, all other terms to the right

10y=-30

y=-30/10

y=-3

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