5(2x-3)-3(3x-5)=4(5-2x)+3(2x+7)

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Solution for 5(2x-3)-3(3x-5)=4(5-2x)+3(2x+7) equation: 



5(2x-3)-3(3x-5)=4(5-2x)+3(2x+7)

We move all terms to the left:

5(2x-3)-3(3x-5)-(4(5-2x)+3(2x+7))=0

We add all the numbers together, and all the variables

5(2x-3)-3(3x-5)-(4(-2x+5)+3(2x+7))=0

We multiply parentheses

10x-9x-(4(-2x+5)+3(2x+7))-15+15=0



We calculate terms in parentheses: -(4(-2x+5)+3(2x+7)), so:

4(-2x+5)+3(2x+7)

We multiply parentheses

-8x+6x+20+21

We add all the numbers together, and all the variables

-2x+41

Back to the equation:

-(-2x+41)



We add all the numbers together, and all the variables

x-(-2x+41)=0

We get rid of parentheses

x+2x-41=0

We add all the numbers together, and all the variables

3x-41=0

We move all terms containing x to the left, all other terms to the right

3x=41

x=41/3

x=13+2/3

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