(5y)+(y+3)+4y-1=82

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Solution for (5y)+(y+3)+4y-1=82 equation: 



(5y)+(y+3)+4y-1=82

We move all terms to the left:

(5y)+(y+3)+4y-1-(82)=0

We add all the numbers together, and all the variables

9y+(y+3)-83=0

We get rid of parentheses

9y+y+3-83=0

We add all the numbers together, and all the variables

10y-80=0

We move all terms containing y to the left, all other terms to the right

10y=80

y=80/10

y=8

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