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(2/3)x-(1/6)=(5/9)
We move all terms to the left:
(2/3)x-(1/6)-((5/9))=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x-(+1/6)-((+5/9))=0
We multiply parentheses
2x^2-(+1/6)-((+5/9))=0
We get rid of parentheses
2x^2-1/6-((+5/9))=0
We calculate fractions
2x^2+()/()+()/()=0
We add all the numbers together, and all the variables
2x^2+2=0
a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation
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