1/6(a-4)=1/3(a+4)

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Solution for 1/6(a-4)=1/3(a+4) equation: 



1/6(a-4)=1/3(a+4)

We move all terms to the left:

1/6(a-4)-(1/3(a+4))=0



Domain of the equation: 6(a-4)!=0

a∈R





Domain of the equation: 3(a+4))!=0

a∈R



We calculate fractions


(3aa/(6(a-4)*3(a+4)))+(-6aa/(6(a-4)*3(a+4)))=0



We calculate terms in parentheses: +(3aa/(6(a-4)*3(a+4))), so:

3aa/(6(a-4)*3(a+4))

We multiply all the terms by the denominator


3aa

Back to the equation:

+(3aa)





We calculate terms in parentheses: +(-6aa/(6(a-4)*3(a+4))), so:

-6aa/(6(a-4)*3(a+4))

We multiply all the terms by the denominator


-6aa

Back to the equation:

+(-6aa)



We get rid of parentheses

3aa-6aa=0

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