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12=e2/48
We move all terms to the left:
12-(e2/48)=0
We add all the numbers together, and all the variables
-(+e2/48)+12=0
We get rid of parentheses
-e2/48+12=0
We multiply all the terms by the denominator
-e2+12*48=0
We add all the numbers together, and all the variables
-1e^2+576=0
a = -1; b = 0; c = +576;
Δ = b2-4ac
Δ = 02-4·(-1)·576
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-1}=\frac{-48}{-2} =+24 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-1}=\frac{48}{-2} =-24 $
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