(5x-6)(7x+2)=0

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Solution for (5x-6)(7x+2)=0 equation:



(5x-6)(7x+2)=0
We multiply parentheses ..
(+35x^2+10x-42x-12)=0
We get rid of parentheses
35x^2+10x-42x-12=0
We add all the numbers together, and all the variables
35x^2-32x-12=0
a = 35; b = -32; c = -12;
Δ = b2-4ac
Δ = -322-4·35·(-12)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-52}{2*35}=\frac{-20}{70} =-2/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+52}{2*35}=\frac{84}{70} =1+1/5 $

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