n+7=n2+2n-35

Solution for n+7=n2+2n-35 equation:

n+7=n2+2n-35

We move all terms to the left:

n+7-(n2+2n-35)=0

We add all the numbers together, and all the variables

-(+n^2+2n-35)+n+7=0

We get rid of parentheses

-n^2-2n+n+35+7=0

We add all the numbers together, and all the variables

-1n^2-1n+42=0

a = -1; b = -1; c = +42;
Δ = b2-4ac
Δ = -12-4·(-1)·42
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-13}{2*-1}=\frac{-12}{-2}
=+6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+13}{2*-1}=\frac{14}{-2}
=-7
$