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(5x+3)=(15-x)
We move all terms to the left:
(5x+3)-((15-x))=0
We add all the numbers together, and all the variables
(5x+3)-((-1x+15))=0
We get rid of parentheses
5x-((-1x+15))+3=0
We calculate terms in parentheses: -((-1x+15)), so:We get rid of parentheses
(-1x+15)
We get rid of parentheses
-1x+15
Back to the equation:
-(-1x+15)
5x+1x-15+3=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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