3x=(68+x)/6

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Solution for 3x=(68+x)/6 equation: 



3x=(68+x)/6

We move all terms to the left:

3x-((68+x)/6)=0

We add all the numbers together, and all the variables

3x-((x+68)/6)=0

We multiply all the terms by the denominator


3x*6)-((x+68)=0

Wy multiply elements

18x^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{36}=0$

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