(5x-2)+12=(3x+20)

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Solution for (5x-2)+12=(3x+20) equation: 



(5x-2)+12=(3x+20)

We move all terms to the left:

(5x-2)+12-((3x+20))=0

We get rid of parentheses

5x-((3x+20))-2+12=0



We calculate terms in parentheses: -((3x+20)), so:

(3x+20)

We get rid of parentheses

3x+20

Back to the equation:

-(3x+20)



We add all the numbers together, and all the variables

5x-(3x+20)+10=0

We get rid of parentheses

5x-3x-20+10=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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