4-x-(2x+5)=x-7(x-2)

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Solution for 4-x-(2x+5)=x-7(x-2) equation: 



4-x-(2x+5)=x-7(x-2)

We move all terms to the left:

4-x-(2x+5)-(x-7(x-2))=0

We add all the numbers together, and all the variables

-1x-(2x+5)-(x-7(x-2))+4=0

We get rid of parentheses

-1x-2x-(x-7(x-2))-5+4=0



We calculate terms in parentheses: -(x-7(x-2)), so:

x-7(x-2)

We multiply parentheses

x-7x+14

We add all the numbers together, and all the variables

-6x+14

Back to the equation:

-(-6x+14)



We add all the numbers together, and all the variables

-3x-(-6x+14)-1=0

We get rid of parentheses

-3x+6x-14-1=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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