(5x+4)(6x-5)=0

Solution for (5x+4)(6x-5)=0 equation:

(5x+4)(6x-5)=0

We multiply parentheses ..

(+30x^2-25x+24x-20)=0

We get rid of parentheses

30x^2-25x+24x-20=0

We add all the numbers together, and all the variables

30x^2-1x-20=0

a = 30; b = -1; c = -20;
Δ = b2-4ac
Δ = -12-4·30·(-20)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-49}{2*30}=\frac{-48}{60}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+49}{2*30}=\frac{50}{60}
=5/6
$