0.05(2t-2)=0.10(t+1)-0.20

Solution for 0.05(2t-2)=0.10(t+1)-0.20 equation:

0.05(2t-2)=0.10(t+1)-0.20

We move all terms to the left:

0.05(2t-2)-(0.10(t+1)-0.20)=0

We multiply parentheses

0.1t-(0.10(t+1)-0.20)-0.1=0


We calculate terms in parentheses: -(0.10(t+1)-0.20), so:

0.10(t+1)-0.20

We add all the numbers together, and all the variables

0.10(t+1)-0.2

We multiply parentheses

0.1t+0.1-0.2

We add all the numbers together, and all the variables

0.1t-0.1

Back to the equation:

-(0.1t-0.1)


We get rid of parentheses

0.1t-0.1t+0.1-0.1=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0