3x+8=35(x+1)3x+8=35(x+1)

Solution for 3x+8=35(x+1)3x+8=35(x+1) equation:

3x+8=35(x+1)3x+8=35(x+1)

We move all terms to the left:

3x+8-(35(x+1)3x+8)=0


We calculate terms in parentheses: -(35(x+1)3x+8), so:

35(x+1)3x+8

We multiply parentheses

105x^2+105x+8

Back to the equation:

-(105x^2+105x+8)


We get rid of parentheses

-105x^2+3x-105x-8+8=0

We add all the numbers together, and all the variables

-105x^2-102x=0

a = -105; b = -102; c = 0;
Δ = b2-4ac
Δ = -1022-4·(-105)·0
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-102}{2*-105}=\frac{0}{-210}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+102}{2*-105}=\frac{204}{-210}
=-34/35
$