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(5x+19)(6x+1)=180
We move all terms to the left:
(5x+19)(6x+1)-(180)=0
We multiply parentheses ..
(+30x^2+5x+114x+19)-180=0
We get rid of parentheses
30x^2+5x+114x+19-180=0
We add all the numbers together, and all the variables
30x^2+119x-161=0
a = 30; b = 119; c = -161;
Δ = b2-4ac
Δ = 1192-4·30·(-161)
Δ = 33481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(119)-\sqrt{33481}}{2*30}=\frac{-119-\sqrt{33481}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(119)+\sqrt{33481}}{2*30}=\frac{-119+\sqrt{33481}}{60} $
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