(4y+12)=72

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Solution for (4y+12)=72 equation: 



(4y+12)=72

We move all terms to the left:

(4y+12)-(72)=0

We get rid of parentheses

4y+12-72=0

We add all the numbers together, and all the variables

4y-60=0

We move all terms containing y to the left, all other terms to the right

4y=60

y=60/4

y=15

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