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(3/10)x-12=(4/5)x-5
We move all terms to the left:
(3/10)x-12-((4/5)x-5)=0
Domain of the equation: 10)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x-5)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/10)x-((+4/5)x-5)-12=0
We multiply parentheses
3x^2-((+4/5)x-5)-12=0
We multiply all the terms by the denominator
3x^2*5)x-5)-((-12*5)x-5)+4=0
We add all the numbers together, and all the variables
3x^2*5)x-5)-((-60)x-5)+4=0
Wy multiply elements
15x^3-60)x-5)+4=0
We do not support expression: x^3
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