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(5x+10)/(2x-8)=0
Domain of the equation: (2x-8)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=8
x!=8/2
x!=4
x∈R
(5x+10)=0
We get rid of parentheses
5x+10=0
We move all terms containing x to the left, all other terms to the right
5x=-10
x=-10/5
x=-2
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