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(x+3)2-8x=12
We move all terms to the left:
(x+3)2-8x-(12)=0
We add all the numbers together, and all the variables
-8x+(x+3)2-12=0
We multiply parentheses
-8x+2x+6-12=0
We add all the numbers together, and all the variables
-6x-6=0
We move all terms containing x to the left, all other terms to the right
-6x=6
x=6/-6
x=-1
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