(x+3)2-8x=12(x+3)

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Solution for (x+3)2-8x=12(x+3) equation: 



(x+3)2-8x=12(x+3)

We move all terms to the left:

(x+3)2-8x-(12(x+3))=0

We add all the numbers together, and all the variables

-8x+(x+3)2-(12(x+3))=0

We multiply parentheses

-8x+2x-(12(x+3))+6=0



We calculate terms in parentheses: -(12(x+3)), so:

12(x+3)

We multiply parentheses

12x+36

Back to the equation:

-(12x+36)



We add all the numbers together, and all the variables

-6x-(12x+36)+6=0

We get rid of parentheses

-6x-12x-36+6=0

We add all the numbers together, and all the variables

-18x-30=0

We move all terms containing x to the left, all other terms to the right

-18x=30

x=30/-18

x=-1+2/3

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