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(5k+1)(5k+10)=9*180
We move all terms to the left:
(5k+1)(5k+10)-(9*180)=0
We add all the numbers together, and all the variables
(5k+1)(5k+10)-1620=0
We multiply parentheses ..
(+25k^2+50k+5k+10)-1620=0
We get rid of parentheses
25k^2+50k+5k+10-1620=0
We add all the numbers together, and all the variables
25k^2+55k-1610=0
a = 25; b = 55; c = -1610;
Δ = b2-4ac
Δ = 552-4·25·(-1610)
Δ = 164025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{164025}=405$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-405}{2*25}=\frac{-460}{50} =-9+1/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+405}{2*25}=\frac{350}{50} =7 $
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