4-1/2(p-1)=3+3/2(p+2)

Solution for 4-1/2(p-1)=3+3/2(p+2) equation:

4-1/2(p-1)=3+3/2(p+2)

We move all terms to the left:

4-1/2(p-1)-(3+3/2(p+2))=0


Domain of the equation: 2(p-1)!=0

p∈R



Domain of the equation: 2(p+2))!=0

p∈R


We calculate fractions


(-2pp/(2(p-1)*2(p+2)))+(-6pp/(2(p-1)*2(p+2)))+4=0


We calculate terms in parentheses: +(-2pp/(2(p-1)*2(p+2))), so:

-2pp/(2(p-1)*2(p+2))

We multiply all the terms by the denominator


-2pp

Back to the equation:

+(-2pp)



We calculate terms in parentheses: +(-6pp/(2(p-1)*2(p+2))), so:

-6pp/(2(p-1)*2(p+2))

We multiply all the terms by the denominator


-6pp

Back to the equation:

+(-6pp)


We get rid of parentheses

-2pp-6pp+4=0

We move all terms containing p to the left, all other terms to the right

-2pp-6pp=-4