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(5a-3)(6a+5)=2
We move all terms to the left:
(5a-3)(6a+5)-(2)=0
We multiply parentheses ..
(+30a^2+25a-18a-15)-2=0
We get rid of parentheses
30a^2+25a-18a-15-2=0
We add all the numbers together, and all the variables
30a^2+7a-17=0
a = 30; b = 7; c = -17;
Δ = b2-4ac
Δ = 72-4·30·(-17)
Δ = 2089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{2089}}{2*30}=\frac{-7-\sqrt{2089}}{60} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{2089}}{2*30}=\frac{-7+\sqrt{2089}}{60} $
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