(x+4)(x+3)=49

Solution for (x+4)(x+3)=49 equation:

(x+4)(x+3)=49

We move all terms to the left:

(x+4)(x+3)-(49)=0

We multiply parentheses ..

(+x^2+3x+4x+12)-49=0

We get rid of parentheses

x^2+3x+4x+12-49=0

We add all the numbers together, and all the variables

x^2+7x-37=0

a = 1; b = 7; c = -37;
Δ = b2-4ac
Δ = 72-4·1·(-37)
Δ = 197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{197}}{2*1}=\frac{-7-\sqrt{197}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{197}}{2*1}=\frac{-7+\sqrt{197}}{2}
$