5(2x+3)+3=(x-2)

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Solution for 5(2x+3)+3=(x-2) equation: 



5(2x+3)+3=(x-2)

We move all terms to the left:

5(2x+3)+3-((x-2))=0

We multiply parentheses

10x-((x-2))+15+3=0



We calculate terms in parentheses: -((x-2)), so:

(x-2)

We get rid of parentheses

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

10x-(x-2)+18=0

We get rid of parentheses

10x-x+2+18=0

We add all the numbers together, and all the variables

9x+20=0

We move all terms containing x to the left, all other terms to the right

9x=-20

x=-20/9

x=-2+2/9

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