4(c-1)=3(4+c)

Solution for 4(c-1)=3(4+c) equation:

4(c-1)=3(4+c)

We move all terms to the left:

4(c-1)-(3(4+c))=0

We add all the numbers together, and all the variables

4(c-1)-(3(c+4))=0

We multiply parentheses

4c-(3(c+4))-4=0


We calculate terms in parentheses: -(3(c+4)), so:

3(c+4)

We multiply parentheses

3c+12

Back to the equation:

-(3c+12)


We get rid of parentheses

4c-3c-12-4=0

We add all the numbers together, and all the variables

c-16=0

We move all terms containing c to the left, all other terms to the right

c=16