(5-11i)(-10-4i)=0

Solution for (5-11i)(-10-4i)=0 equation:

(5-11i)(-10-4i)=0

We add all the numbers together, and all the variables

(-11i+5)(-4i-10)=0

We multiply parentheses ..

(+44i^2+110i-20i-50)=0

We get rid of parentheses

44i^2+110i-20i-50=0

We add all the numbers together, and all the variables

44i^2+90i-50=0

a = 44; b = 90; c = -50;
Δ = b2-4ac
Δ = 902-4·44·(-50)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-130}{2*44}=\frac{-220}{88}
=-2+1/2
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+130}{2*44}=\frac{40}{88}
=5/11
$