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2(x-5)+4(3x-12)=96
We move all terms to the left:
2(x-5)+4(3x-12)-(96)=0
We multiply parentheses
2x+12x-10-48-96=0
We add all the numbers together, and all the variables
14x-154=0
We move all terms containing x to the left, all other terms to the right
14x=154
x=154/14
x=11
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