(n+4)+(n+2)+n=0

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Solution for (n+4)+(n+2)+n=0 equation: 



(n+4)+(n+2)+n=0

We add all the numbers together, and all the variables

n+(n+4)+(n+2)=0

We get rid of parentheses

n+n+n+4+2=0

We add all the numbers together, and all the variables

3n+6=0

We move all terms containing n to the left, all other terms to the right

3n=-6

n=-6/3

n=-2

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