(x+5)(x-5)+(x-2)*(x-2)=(x-5)*(x-5)+(x*x+14)

Solution for (x+5)(x-5)+(x-2)*(x-2)=(x-5)*(x-5)+(x*x+14) equation:

(x+5)(x-5)+(x-2)(x-2)=(x-5)(x-5)+(x*x+14)

We move all terms to the left:

(x+5)(x-5)+(x-2)(x-2)-((x-5)(x-5)+(x*x+14))=0

We use the square of the difference formula

x^2+(x-2)(x-2)-((x-5)(x-5)+(x*x+14))-25=0

We multiply parentheses ..

x^2+(+x^2-2x-2x+4)-((x-5)(x-5)+(x*x+14))-25=0


We calculate terms in parentheses: -((x-5)(x-5)+(x*x+14)), so:

(x-5)(x-5)+(x*x+14)

We get rid of parentheses

(x-5)(x-5)+x*x+14

We multiply parentheses ..

(+x^2-5x-5x+25)+x*x+14

Wy multiply elements

(+x^2-5x-5x+25)+x^2+14

We get rid of parentheses

x^2+x^2-5x-5x+25+14

We add all the numbers together, and all the variables

2x^2-10x+39

Back to the equation:

-(2x^2-10x+39)


We get rid of parentheses

x^2+x^2-2x^2-2x-2x+10x+4-39-25=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10