(5-10x)(6x+3)=0

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Solution for (5-10x)(6x+3)=0 equation:



(5-10x)(6x+3)=0
We add all the numbers together, and all the variables
(-10x+5)(6x+3)=0
We multiply parentheses ..
(-60x^2-30x+30x+15)=0
We get rid of parentheses
-60x^2-30x+30x+15=0
We add all the numbers together, and all the variables
-60x^2+15=0
a = -60; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-60)·15
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-60}=\frac{-60}{-120} =1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-60}=\frac{60}{-120} =-1/2 $

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