5(r-2)=4(r-3)+4

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Solution for 5(r-2)=4(r-3)+4 equation: 



5(r-2)=4(r-3)+4

We move all terms to the left:

5(r-2)-(4(r-3)+4)=0

We multiply parentheses

5r-(4(r-3)+4)-10=0



We calculate terms in parentheses: -(4(r-3)+4), so:

4(r-3)+4

We multiply parentheses

4r-12+4

We add all the numbers together, and all the variables

4r-8

Back to the equation:

-(4r-8)



We get rid of parentheses

5r-4r+8-10=0

We add all the numbers together, and all the variables

r-2=0

We move all terms containing r to the left, all other terms to the right

r=2

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