(4y+8)+(5y-3)=7y+15

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Solution for (4y+8)+(5y-3)=7y+15 equation: 



(4y+8)+(5y-3)=7y+15

We move all terms to the left:

(4y+8)+(5y-3)-(7y+15)=0

We get rid of parentheses

4y+5y-7y+8-3-15=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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