If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(5x-5)+(2x+11)=41
We move all terms to the left:
(5x-5)+(2x+11)-(41)=0
We get rid of parentheses
5x+2x-5+11-41=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5
| 1^1/2+2x=6^1/2 | | u2+6u−27=0 | | 7+4y=-6 | | |-x-3|=5 | | x-0.9x=100 | | 6Q=24-3p | | X-1/11+2x+1/7=7x-4/22+x+4/14 | | x-0.02x=58500 | | 24=4(k-5) | | x-0.02x=66000 | | x-0.02x=660000 | | 0.911=x/0.2-x | | x/0.2-x=0.9110433579 | | x-0.02x=50000 | | x+-0.02x=50000 | | 3^x(9^(x+1))=60 | | C=30(40x+25)+15 | | y+0.7=12 | | 5y-2(2y-7)=2(3y-1)+7/4 | | -36=-9(x+11) | | 6x+-35+3x+53=180 | | -9x+7=15x-1 | | 20x+6=-19 | | 14x-1=28x+7 | | 10x-2=-10x-8 | | 4(3+2y)=4 | | 5(x)+15=5(x+3) | | 13=4z+6 | | 4=5z-11 | | 3u+1=14 | | |2x+3|-4=11 | | 5(z-3)+11=1 |