8-(y-3)=5(y+1)

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Solution for 8-(y-3)=5(y+1) equation: 



8-(y-3)=5(y+1)

We move all terms to the left:

8-(y-3)-(5(y+1))=0

We get rid of parentheses

-y-(5(y+1))+3+8=0



We calculate terms in parentheses: -(5(y+1)), so:

5(y+1)

We multiply parentheses

5y+5

Back to the equation:

-(5y+5)



We add all the numbers together, and all the variables

-1y-(5y+5)+11=0

We get rid of parentheses

-1y-5y-5+11=0

We add all the numbers together, and all the variables

-6y+6=0

We move all terms containing y to the left, all other terms to the right

-6y=-6

y=-6/-6

y=1

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